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2y^2-19y-60=0
a = 2; b = -19; c = -60;
Δ = b2-4ac
Δ = -192-4·2·(-60)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-29}{2*2}=\frac{-10}{4} =-2+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+29}{2*2}=\frac{48}{4} =12 $
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